c# Regex to match end of string?

Question

I need help to generate regex so that it will match any string which has following detail correct:

String should end with bracket and only numbers inside it.
End bracket should appear only once at the end of line and not any where else.
Any characters are allowed before bracket start
No characters are allowed after bracket end
String should contain only 1 set of brackets with numbers, i.e. no double brackets like (( or ))

I have tried this .$[0-9]+$$ but this is not what i required.

For example:

Following string should match:

asds-xyz (1)
asds+-xyz (12)
as@ds-xyz (123)

Following strings should not be matched:

asds-xyz ((1)
asds-xyz ((12sdf))
(123) asds-xyz
xyz ((2)
XYX (1))
XYZ (1)(2)
xyz(1)BXZ
xyz(1)BXZ(2)

Sebastian Schumann · Accepted Answer · 2015-07-10 05:48:00Z

2

^[^\(\)]*\(\d+\)$

will do the job...

\d = [0-9]

edited Jul 10, 2015 at 5:48

answered Jul 10, 2015 at 5:41

Sebastian Schumann

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1 Comment

Sandeep Over a year ago

Thanks. Its working fine with test strings. negate group is what i was missing

n00b · Accepted Answer · 2015-07-10 05:38:25Z

1

I try to fix with minimum change to your pattern: you have to use the [^ key to exclude brackets before your only desired bracket. like this

[^\(\)]*\([0-9]+\)$

That would find the patterns you like, and if you like the whole string to be like that, then simply add a ^ in the beginning

answered Jul 10, 2015 at 5:38

n00b

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3 Comments

Sebastian Schumann Over a year ago

It matches XYZ (1)(2), asds-xyz ((1), xyz ((2) and xyz(1)BXZ(2) but shouldn't.

n00b Over a year ago

@Verarind no, with ^ in the beginning it will not

Sebastian Schumann Over a year ago

test it! Your regex says no bracket [^] for any times *. Any could be zero and that happens in all of the specified cases. But what's about the second fact that a brace shouln'd come anywhere in the string but the end? You need an ancor ^ that all from begining should not be a bracked. But this ancor is missing.

Liem Do · Accepted Answer · 2015-07-10 05:38:42Z

-1

Starting from your regex: .$[0-9]+$$ . match everything but you need quantifier for this. So add * to this .*$[0-9]+$$ But the problem is, it will match ( and ) before the last bracket like xyz ((2) So make a negative set for this, the final result:

^(.*[^\(\)])(\([0-9]+\))$

answered Jul 10, 2015 at 5:38

Liem Do

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1 Comment

Sebastian Schumann Over a year ago

It matches xyz(1)BXZ(2) but shouldn't.

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