PHP - How to echo Value from Multidimensional Array

Question

I have:

$request = Array
(
    [ID] => 2264
    [SUCCESS] => Array
        (
            [0] => Array
                (
                    [MESSAGE] => Service Details
                    [LIST] => Array
                        (
                            [retail_name] => 
                            [credit_admin] => FREE
                            [credit] => 0
                            [discount_admin] => 0
                            [discount] => 0
                            [cartdiscount] => 0

If I do:

echo $request[ID];                            // it says: 2264
echo $request[SUCCESS];                       // it says: Array
echo $request[SUCCESS][0][MESSAGE];           // it says: Service Details

But I need to echo "credit" and if I do:

echo $request[SUCCESS][0][LIST];           // I get ERROR
echo $request[SUCCESS][0][LIST][credit];   // I get ERROR

I dont understand why? How can I do it? Thank you

Try as echo $request['SUCCESS'][0]['LIST']['credit']; if it won't work post your error too — Narendrasingh Sisodia
– Narendrasingh Sisodia, Commented Jul 10, 2015 at 5:54
Check this post it may help you to debug it stackoverflow.com/questions/13018280/… — George_v
– George_v, Commented Jul 10, 2015 at 5:56
@Uchiha Thank you, that worked!!! Hmm.. So always should use ' ? — Cyborg
– Cyborg, Commented Jul 10, 2015 at 5:57
Yes I personally always prefer quotes and it can be " or ' — Narendrasingh Sisodia
– Narendrasingh Sisodia, Commented Jul 10, 2015 at 5:58
@NarendrasinghSisodia please consider to write your comment as an Answer or upvote/downvote answers below so I can mark this question as Solved. Thank you so much for all your great help. — Cyborg
– Cyborg, Commented Jul 9, 2017 at 18:22

AgeDeO · Accepted Answer · 2015-07-10 06:02:18Z

1

You aren't using quotes to specify the array keys. you should use ['ID'] instead of [ID]

PHP fixes this for you and presumes you meant ['ID'] instead of [ID] and trows a notice in the logs

This doen't work for [LIST] however because LIST is a reserved keyword. That means that list has a function in PHP. PHP doesn't know which one you need and doesn't return result.

Change [LIST] to ['LIST'] and you should recieve your values. Please learn to use arrays with quotes, to prevent errors like this in the future

answered Jul 10, 2015 at 6:02

AgeDeO

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2 Comments

Narendrasingh Sisodia Over a year ago

List is not really a function, but a language construct. list() is used to assign a list of variables in one operation.

AgeDeO Over a year ago

@Uchiha : That is why I mentioned it has a function within PHP not that it is a function in PHP ;)

JSowa · Accepted Answer · 2020-05-09 08:08:41Z

0

Previously every string without quotes was treated like string if there was no Constant defined under this name, but from PHP 7.2 now issues error of level E_WARNING. Why is $foo[bar] wrong?

PHP Warning:  Use of undefined constant test - assumed 'test' (this will throw an Error in a future version of PHP)

In this example list is treated as construct list(). Using bare strings in associative arrays as keys is deprecated and should be avoided.

Correct way is to call it with quotes (single or double):

echo $request['SUCCESS'][0]['LIST'];
echo $request['SUCCESS'][0]['LIST']['credit'];

answered May 9, 2020 at 8:08

JSowa

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Comments

Meenesh Jain · Accepted Answer · 2015-07-10 06:19:56Z

0

Depends on Your Key and Value

If your array key has a value it will directly output that

for ex

 echo $request[ID];

b'coz id directly holds a value;

But

$request[SUCCESS]; 

// holds an array. you cannot echo a array directly 
// to do something like this you will need the key of your inner 
// array with outer array in combinations to echo the values

for ex

 echo $request[SUCCESS][0]['MESSAGE'];

// Key "O" holds an array also. so you need to use its inner array keys

same needs to be done for

 echo $request[SUCCESS][0]['MESSAGE']['LIST']['credit_admin']; 
 // where again list is a array

answered Jul 10, 2015 at 6:19

Meenesh Jain

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