Using array index outside of the allocated memory appears fine, how? [duplicate]

Question

int main (){

    int number[5];

    number[0]=45;
    number[1]=12;
    number[2]=555;
    number[5]=89;
    number[6]=46; 

    printf("%d",number[6]); 
}

As we know, we're not supposed to access array out-of-bounds. Here, how the number[6] can be executable?

Sourav Ghosh · Accepted Answer · 2015-07-13 11:38:51Z

4

how the number[6] can be executable

^{I'll humbly suggest to use "accessible" instead of "executable"}

Point 1. Both the number[5] and number[6] are out of bound. Remember, C uses 0 based index for arrays.
Point 2. Accessing out of bound memory causes undefined behaviour. This includes all sorts of strange behaviours.

answered Jul 13, 2015 at 11:38

Sourav Ghosh

135k17 gold badges192 silver badges271 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Raman · Accepted Answer · 2015-07-13 11:38:56Z

2

Going outside the limits of any array leads to undefined behavior

You have declared number to be an array of size 5. And you are trying to use number[5] and number[6]. This is an undefined behavior.

answered Jul 13, 2015 at 11:38

Raman

2,8052 gold badges31 silver badges48 bronze badges

Collectives™ on Stack Overflow

Using array index outside of the allocated memory appears fine, how? [duplicate]

2 Answers 2

Comments

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Linked

Related