Comparing consequent strings in Python

Question

Right now I have a string array and I want to loop through the string array and compare the value at one index with the value at the next index. For example, if I was doing this in Java, the code would be something like this:

string[] some = ["IP", "IP", "ADDRESS", "2342.42.2", "IP", "ASDF"];
for (int i = 0 ; i < some.length() ; i++)
    if (some[i] == "IP" && some[i+1] == "ADDRESS")
        int ipaddress = some[i+2];

I know that Python is a bit different, but basically I am trying to find the first IP ADDRESS. How can I compare the current element and the next one in a loop?

Bhargav Rao · Accepted Answer · 2015-07-14 17:53:50Z

1

This is a direct translation of your code. In python enumerate iterates over a list as index,value pairs.

>>> some = ["IP", "IP", "ADDRESS", "2342.42.2", "IP", "ASDF"];
>>> for i,v in enumerate(some):
...     if v=="IP" and some[i+1] == "ADDRESS": 
...         ipaddress = some[i+2]
... 
>>> ipaddress
'2342.42.2'

However you may consider end cases where there is no such stuff. So you may as well so for i,v in enumerate(some[:-2]). This will ensure that you will not get out of the bounds of the list otherwise you will get an IndexError

edited Jul 14, 2015 at 17:53

answered Jul 14, 2015 at 17:50

Bhargav Rao

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3 Comments

trynacode Over a year ago

Yeah I just figured it out right after I asked the question...silly on my part. I did something like this:

for index in range(len(datainarray)): 		print 'Current string :' , datainarray[index] 		if datainarray[index] == "IP" and datainarray[index + 1] == "ADDRESS": 			print "HERES ONE"

Bhargav Rao Over a year ago

Using enumerate is the preferred way in Python

trynacode Over a year ago

Oh alright. Will look into that and use that instead then!

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