Convert JSON in C# to an Object using JsonConvert

Question

I am trying to deserialize my JSON notation to an object. I'm getting this error: {"'Newtonsoft.Json.Linq.JProperty' does not contain a definition for 'id'"}

Here is my JSON represented in json3:

string json3 = "{'Rows':[{'id':'1017','ischecked':'true'},{'id':'1018','ischecked':'false'}]}"

Here is my c# code:

dynamic dynJson = JsonConvert.DeserializeObject(json3);
foreach (var item in dynJson)
{
    Console.WriteLine("{0} {1}\n", item.id, item.ischecked);
}

Is my JSON not formed correctly? It seems like this should be pretty straight forward.

Did you stop and inspect dynJson in the debugger to make sure you have the right code? — crashmstr
– crashmstr, Commented Jul 16, 2015 at 18:50
Have you noticed that you have given a " after the first id? I think it should be '. — Utsav Dawn
– Utsav Dawn, Commented Jul 16, 2015 at 18:55

Pranay Rana · Accepted Answer · 2015-07-16 18:59:46Z

4

why dont you crete object like this and desrialize it

public class Row
{
    public int ID { get; set; }
    public bool ischecked { get; set; }

}
List<Row> list = JsonConvert.DeserializeObject<List<Row>>(stringofjson);

if it dont work than try this way

public class RowJson
{
   [JsonProperty("Rows")]
   public Row Row { get; set; }
}
public class Row
{
    public int ID { get; set; }
    public bool ischecked { get; set; }

}
List<RowJson> list = JsonConvert.DeserializeObject<List<RowJson>>(stringofjson);

edited Jul 16, 2015 at 18:59

answered Jul 16, 2015 at 18:53

Pranay Rana

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1 Comment

James Bailey Over a year ago

Pranay, No luck with either. The bottom yields: 'Newtonsoft.Json.JsonSerializationException' occurred in Newtonsoft.Json.dll but was not handled in user code Additional information: Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[WebApplication1.Controllers.RowJson]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.

James Bailey · Accepted Answer · 2015-07-17 02:14:41Z

Thanks Pranay, here is what I finally used. You were very close and got me down the right path. The code below works on both formats of JSON, each represented in the variables json2 and json3.

Classes:

using Newtonsoft.Json;

public class CheckBoxResultsJson
{
    public List<boCheckBoxResult> checkboxes { get; set; }
}
public class boCheckBoxResult
{
    public int id { get; set; }
    public bool ischecked { get; set; }
}

Code to consume the JSON:

        //string json2 = "{\"checkboxes\":[{\"id\":\"1018\",\"ischecked\":\"true\"},{\"id\":\"1019\",\"ischecked\":\"true\"},{\"id\":\"1020\",\"ischecked\":\"true\"},{\"id\":\"1017\",\"ischecked\":\"true\"},{\"id\":\"1021\",\"ischecked\":\"true\"},{\"id\":\"18\",\"ischecked\":\"true\"}]}";
        string json3 = "{'checkboxes':[{'id':'1017','ischecked':'true'},{'id':'1018','ischecked':'false'}]}";


        //CheckBoxResultsJson checkBoxResultJson = (CheckBoxResultsJson)JsonConvert.DeserializeObject(json2, typeof(CheckBoxResultsJson));
        CheckBoxResultsJson checkBoxResultJson = (CheckBoxResultsJson)JsonConvert.DeserializeObject(json3, typeof(CheckBoxResultsJson));
        Console.WriteLine(checkBoxResultJson.checkboxes.Count.ToString());
        foreach(boCheckBoxResult x in checkBoxResultJson.checkboxes)
        { 
            int id = x.id;

        }

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