get url parameter in php with $GET

Question

I am passing a parameter in my URL address which I want to use in my PHP to build a directory path which will then be used by the PHP as image directory to build HTML

My URL is:- http://www.icrrc.x10host.com/Pages/gallery-test1.php?galleryName=General

My PHP is:

$gallery = 'Images/Gallery/'$_GET['galleryName'];

I then use $gallery to build the img src=image filenames in my HTML

My problem is with the $_GET, I am being returned:

Parse error: syntax error, unexpected '$_GET' (T_VARIABLE) in /home/icrrcx10/public_html/Pages/gallery-test1.php on line 111

Can anyone suggest what is wrong with my syntax as I am a newbie to php?

Unni Babu · Accepted Answer · 2015-07-18 09:27:43Z

1

There is a problem with your syntax, corrected and shown below

$gallery = "Images/Gallery/".$_GET['galleryName'];

answered Jul 18, 2015 at 9:27

Unni Babu

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2 Comments

alan Over a year ago

Thanks Unni Babu I thought it would be something easy

Unni Babu Over a year ago

@alan... if this helps :) dont forget to select this as answer...always welcome

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