java :loop user inputs individually

Question

I have a program which tells the user to input three ints and converts each one to a string. I.e 1 = one ; ...etc. The problem here is defining the ints for every user input. How can i get it with just one input and loop it to take another, considering to separate inputs so we can use it individually in every phrase down here.

public static void main(String[] args) {

    String[] i = { "zero" , "one" , "two" , "three" , "four" , 
                    "five", "six", "seven" , "eight" , "nine" , "ten" };

    Scanner in = new Scanner(System.in);

    System.out.println("I have ..... Networking books, ..... Database books, and ..... Programming books. ");

    String text = "" , text1 = "", text2 = "" ;    
    // loop i/p and using it in every phrase seperatellty 

    for (int a = 1; a <= 1; a++) {
        int word = in.nextInt();
        int word1 = in.nextInt();
        int word2 = in.nextInt();

        text = i[word];
        text1 = i[word1]; 
        text2 = i[word2]; 
    }

    System.out.println("I have " + text + " Networking books, "
                                        + text1 + "  Database books, and " 
                                        + text2 +" Programming books. ");

}}

Why do you want to loop??

ganeshvjy
– ganeshvjy

2015-07-21 03:50:02 +00:00
Commented Jul 21, 2015 at 3:50 — ganeshvjy
– ganeshvjy, Commented Jul 21, 2015 at 3:50
it just an assignment tells me to do !

mostafa magdy
– mostafa magdy

2015-07-21 04:13:46 +00:00
Commented Jul 21, 2015 at 4:13 — mostafa magdy
– mostafa magdy, Commented Jul 21, 2015 at 4:13

sakthisundar · Accepted Answer · 2015-07-21 04:06:32Z

2

Perhaps this is what you are trying to do

Note:

You have missed range check for the entered no. This will throw ArrayIndexOutOfBoundExceptionif you are trying to access the array i for indices above 10

import java.util.*;
class UserInputReader {

    private static final int EXPECTED_NUM_COUNT = 3;

    public static void main(String[] args) {
        String [] i = { "zero" , "one" , "two" , "three" , "four" , 
                    "five", "six", "seven" , "eight" , "nine" , "ten" };

        Scanner in = new Scanner (System.in);   
        String[] words = new String[EXPECTED_NUM_COUNT];

        int numCount = 0;
        while(numCount < 3) {
            System.out.println("Enter the number");
            int num = in.nextInt();
            if (num >= 0 && num <= 10) {
                words[numCount] = i[num];
                numCount++;
            } else {
                System.out.println("Enter no is invalid. Try again entering a number between 0 - 10");
            }
        }

        System.out.println("Entered nums " + Arrays.toString(words));

    }
}

answered Jul 21, 2015 at 4:06

sakthisundar

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2 Comments

sakthisundar Over a year ago

Hey, no problem and welcome. Glad that I could help.

mostafa magdy Over a year ago

this is what i wanted instead of define int for every input , just make it array and use it,s element to compare , thanks :D { System.out.println("I have "+ words[0]+ " Networking books," + words[1] +" Database books, and "+words[2]+ " Programming books.") ;

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