Regular expression powershell

Question

What is the regular expression in powershell for reading the values between "JPEG" and "5."

JPEG_5.10.002.000.txt
JPEG_pnrl_5.10.002.000.txt
JPEG_pnrl_Explorer_5.10.002.000.txt
jpeg_fsrg_5.10.002.000.txt
JPEG_Help_5.10.002.000.txt
JPEG_5.10.002.001.txt
JPEG_pnrl_5.10.002.001.txt
JPEG_Help_5.10.002.001.txt
JPEG_pnrl_Explorer_5.10.002.002.txt
JPEG_fsrg_5.20.002.002.txt
JPEG_Help_5.20.002.002.txt
JPEG_pnrl_5.20.002.003.txt
JPEG_fsrg_5.20.002.003.txt

I used the following regex for getting the value but it is not working.What is the best pattern for getting the value between "JPEG" and "5."

$r = [regex] "[JPEG]+([a-zA-Z]+).*"
$match = $r.match("JPEG_pnrl_Explorer_5.10.002.000.txt")
$text = $match.groups[1].value

Steven Doggart · Accepted Answer · 2015-07-23 19:11:03Z

2

Try JPEG(.*?)5

There's no need to capture the entire string. That will capture everything up through the first 5. The ? makes it non-greedy, so it won't capture up through the last 5.

answered Jul 23, 2015 at 19:11

Steven Doggart

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