Getting a php variable inside javascript click()?

Question

How can I get a php variable inside javascript click()? My click() code is

$(".sample_icons").click(function(){
	var $srcimg=$(this).children("img").attr('src');
	image_icon($srcimg);
});

I have a variable $price in a php file and i want something to happen to this variable say increase price when this click() is used. Click() is in a js file. So how can I pass this variable to js file so that it can be used under click()?

possible duplicate of How to pass variables and data from PHP to JavaScript? — Matthias A. Eckhart
– Matthias A. Eckhart, Commented Jul 25, 2015 at 9:16
Already answered here stackoverflow.com/questions/17314926/… and here stackoverflow.com/questions/13840429/… — Antony
– Antony, Commented Jul 25, 2015 at 9:16
You can’t alter PHP variable values with JavaScript. The PHP script has been processed by the time the web page is rendered on your screen. PHP is a server side language, JavaScript a client side language. — Martin Bean
– Martin Bean, Commented Jul 25, 2015 at 12:42
@AbyBasheer You can’t “integrate” them. They’re ran at different times. PHP has finished doing its thing by the time JavaScript comes into the equation. You can’t change PHP variables with JavaScript. — Martin Bean
– Martin Bean, Commented Jul 25, 2015 at 14:23

shadryck · Accepted Answer · 2015-07-25 12:39:22Z

1

Put this into wherever you need the php variable to be.

<?php echo $price ?>

answered Jul 25, 2015 at 12:39

shadryck

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2 Comments

Aby Over a year ago

so if I add $(".sample_icons").click(function(){ var $srcimg=$(this).children("img").attr('src'); image_icon($srcimg); <?php echo $price ?> }); whether I will get the value of variable price?

shadryck Over a year ago

If you have $price set, then the whole code block above will be replaced with the value of $price.

shadryck · Accepted Answer · 2015-07-25 12:58:58Z

0

I make use of a hidden input:

<input type="hidden" id="this_price" value="<?php echo $price ?>">

$(".sample_icons").click(function(){
    var this_price = $('#this_price').val();
    var $srcimg=$(this).children("img").attr('src');
    image_icon($srcimg);
});

edited Jul 25, 2015 at 12:58

shadryck

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answered Jul 25, 2015 at 12:51

petebolduc

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