Lua iterating string for whitespace

Question

whiteSpace = 0
foo = "foo bar"

for i = 1, #foo do
    if (string.sub(foo, i, i) == "%") then
        whiteSpace = whiteSpace + 1
    end
end

print(whiteSpace)

I'm trying to loop through this string in each character, check if it is whitespace. If the character is whitespace, I want to increment the whiteSpace variable and output it at the end. But for some reason when I execute it, it always returns 0, even though there is clearly whitespace within the foo string.

I've used "%", "%s" and "" with no avail. Pretty clueless right now.

Yu Hao · Accepted Answer · 2015-07-26 09:49:02Z

3

whiteSpace = 0
foo = "foo bar"

for i = 1, #foo do
    if (string.sub(foo, i, i) == " ") then
        whiteSpace = whiteSpace + 1
    end
end

print(whiteSpace)

with pattern matching

a, whiteSpace = string.gsub("foo bar","%s","")
print(whiteSpace)

edited Jul 26, 2015 at 9:49

Yu Hao

123k50 gold badges252 silver badges305 bronze badges

answered Jul 26, 2015 at 4:58

Horacio

2,9951 gold badge16 silver badges26 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Yu Hao · Accepted Answer · 2015-07-26 09:49:16Z

1

whiteSpace = 0
foo = "foo bar"
foo = string.gsub(foo, "%s", " ")

for i = 1, #foo do
    if (string.sub(foo, i, i) == " ") then
        whiteSpace = whiteSpace + 1
    end
end

print(whiteSpace)

edited Jul 26, 2015 at 9:49

Yu Hao

123k50 gold badges252 silver badges305 bronze badges

answered Jul 26, 2015 at 5:05

nokizorque

572 silver badges6 bronze badges

Collectives™ on Stack Overflow

Lua iterating string for whitespace

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related