How to modify this Json Output in PHP?

Question

Bellow are Dynamic Output for E-ticket

{
   charting: "CNP"
}

To - chart not prepared

{
    charting: "CP"
}

To - chart prepared

How to change this output in PHP

Thanks

can you add more details that how do you get this output and what is the source, what you have tried — Meenesh Jain
– Meenesh Jain, Commented Jul 28, 2015 at 6:34
I use third party API and its showing this status for chart prepared or not with only "CNP" and "CP" I need to convert both in full text like - chart not prepared and chart prepared version — Olivia Nielsen
– Olivia Nielsen, Commented Jul 28, 2015 at 6:36

Vico · Accepted Answer · 2015-07-28 06:44:33Z

1

You can use json_decode() to get the data, change the data as you need, and use json_encode() to encode it again.

e.g

<?php
$json = '{
   "charting": "CNP"
}';
$phpArray = json_decode($json, true);


if($phpArray['charting'] == 'CP'){
    $phpArray['charting'] = 'chart prepared';
}else if($phpArray['charting'] == 'CNP'){
    $phpArray['charting'] = 'chart not prepared';
}


echo json_encode($phpArray);
?>

edited Jul 28, 2015 at 6:44

answered Jul 28, 2015 at 6:38

Vico

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3 Comments

Olivia Nielsen Over a year ago

This both values are not same every time so how could I encode it?

Vico Over a year ago

I edited my post @OliviaNielsen, is it what you are looking for?

Vico Over a year ago

You're welcome. Please consider marking your question as solved if everything works fine for you!

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