custom django-admin commands - AttributeError: 'Command' object has no attribute 'stdout'

Question

Following the example of writing a custom django-admin command here, I've created the following custom command:

from django.core.management.base import BaseCommand, CommandError

class Command(BaseCommand):
    args = ''
    help = 'Test command'

    def handle(self, *args, **options):
        self.stdout.write("Hello World!")

Surprisingly, I receive the following stack trace:

Traceback (most recent call last):
  File "D:\My Documents\Dev\MyProject\svn\trunk\dj_project\manage.py", line 11, in <module>
    execute_manager(settings)
  File "C:\Python26\lib\site-packages\django\core\management\__init__.py", line 438, in execute_manager
    utility.execute()
  File "C:\Python26\lib\site-packages\django\core\management\__init__.py", line 379, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "C:\Python26\lib\site-packages\django\core\management\base.py", line 191, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "C:\Python26\lib\site-packages\django\core\management\base.py", line 218, in execute
    output = self.handle(*args, **options)
  File "D:\My Documents\Dev\MyProject\svn\trunk\dj_project\..\dj_project\dj_app\management\commands\mytest.py", line 8, in handle
    self.stdout.write("Hello World!")
AttributeError: 'Command' object has no attribute 'stdout'

How come? This is a very basic custom command that as far as I understand conforms to the example.

I'm using django 1.2.1

Willi Müller · Accepted Answer · 2013-10-09 15:40:28Z

20

Since this is the first hit on Google I'll write another solution to another problem with the same error message: If your class Command implements __init__, it has to call __init__ of the superclass.

This will work:

from django.core.management.base import BaseCommand

class Command(BaseCommand):

    def __init__(self, *args, **kwargs):
        super(Command, self).__init__(*args, **kwargs)
        ... do stuff

This won't work:

from django.core.management.base import BaseCommand

class Command(BaseCommand):

    def __init__(self, *args, **kwargs):
       ... do stuff

answered Oct 9, 2013 at 15:40

Willi Müller

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1 Comment

maxicecilia Over a year ago

This worked for me, the current correct answer is too old now

mlissner · Accepted Answer · 2014-10-22 20:24:17Z

6

There are two easy solutions here. The simple one is to simply convert all of your self.stdout lines to print statements instead.

That's an OK solution and you can do it.

The better solution, since self.stdout is set up in the execute() method, is to...run the execute() method.

So instead of:

Command().handle()

Do:

Command().execute()

That'll set up the self.stdout variable correctly and you'll be off and running.

answered Oct 22, 2014 at 20:24

mlissner

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2 Comments

wei Over a year ago

This answer should be picked as hte best answer!

just10minutes Over a year ago

Thank you for this suggestion. Can anyone confirm is there any real difference between handle and execute? I have just changed my handle definition to execute and i am getting the desired result. But little concern is there any actual benefit of using handle in place of execute.

Daniel Roseman · Accepted Answer · 2010-07-02 18:15:27Z

4

It looks like the mapping to self.stdout is a very new change in Django's trunk version, committed in May. If you're running the 1.2 release or earlier, this won't work - and you should be using the earlier documentation.

answered Jul 2, 2010 at 18:15

Daniel Roseman

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3 Comments

Jonathan Livni Over a year ago

I'm running django 1.2.1 so still need an answer. Will update the question.

Daniel Roseman Over a year ago

I don't know why my answer wasn't satisfactory. Django 1.2.1 was released on May 24, this change was made on June 6.

Roman Starkov Over a year ago

@Jonathan: just replace "self.stdout.write" with "print". @Daniel I think your answer would benefit from mentioning the actual fix. But +1 because it helped me with my problem :)

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