Sort Un-ordered XML using Java

Question

I want to sort un-ordered XML files so that two files can be comparable. XML file should be sorted based on first outermost tag and then inner tags. I want some generic code. For Example:

My XML file is :

<xn:rootElement>
    <subs:Parent id="2">
        <subs:Child1 id="2">
            <attributes>
                <attribute1></attribute1>
                <attribute2></attribute2>
            <attributes>
        </subs:Child1>

    </subs:Parent>
    <subs:Parent id="2">
        <subs:Child1 id="1">
            <attributes>
                <attribute1></attribute1>
                <attribute2></attribute2>
            <attributes>
        </subs:Child1>
    </subs:Parent>
</xn:rootElement>

I want the following result, as parent id is same it is sorted on base of child element.

<xn:rootElement>
    <subs:Parent id="2">
        <subs:Child1 id="1">
            <attributes>
                <attribute1></attribute1>
                <attribute2></attribute2>
            <attributes>
        </subs:Child1>

    </subs:Parent>
    <subs:Parent id="2">
        <subs:Child1 id="2">
            <attributes>
                <attribute1></attribute1>
                <attribute2></attribute2>
            <attributes>
        </subs:Child1>
    </subs:Parent>
</xn:rootElement>

Need to check every possibility , if parenet id is same then sort on base of child id.

Note: Size of XMLs is very Large.

Thanks a lot in advance.

I tried with XSLT but in that case i need to specify the tag with which i want to sort in style-sheet. I tried with SAXBuilder but i am not satisfied because it is not even generic code. I want some generic code. — Shikha Gupta
– Shikha Gupta, Commented Jul 29, 2015 at 7:35
Convert your XML to Java Objects using JAXB or any other method you find it suitable, override equals and hashCode and compare Objects. Comparing XMLs as a String is not a good approach. — Zaid Malhis
– Zaid Malhis, Commented Jul 29, 2015 at 7:41
how large is your xml. You said that you tried using xslt. did xslt transformation succeeded without OutOfMemory error. — Santhosh Kumar Tekuri
– Santhosh Kumar Tekuri, Commented Jul 29, 2015 at 7:44

Chowdappa · Accepted Answer · 2015-07-29 08:23:02Z

1

I don't have code ready to share. but Pseudocode is:

Try creating objects with Parent and having list of childs.
Sort the list of parents and its respective childs.
Create a XML again.

answered Jul 29, 2015 at 8:23

Chowdappa

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