JSON to Array using PHP json_decode

Question

I'm reading a json file using

$jsonStr = file_get_contents("connection.json");
$jsonParsed = json_decode($jsonStr,true);

and I want $jsonParsed to be a associative array like this:

$jsonParsed = { "SERVER" => "111.222.333.444" , "USER" => "edvaldo" , "PASSWORD" => "my_password_here", "DATABASE" => "my_database_here" };

What is the format of the JSON needed to do this?

I tried this

{
    "SERVER": "111.222.333.444",
    "USER": "edvaldo",
    "PASSWORD": "my_password_here",
    "DATABASE": "my_database_here"
}

but even with JSONLint saying this piece og JSON is valid, I can't get the result I need.

I'm not really very used to JSON and then I will appreciate a lot any help given.

EDITED:

This is the function I'm using:

private function set_mysql_parameters() {
    $this->connectionParams = array();
    $json_file = $this->system_paths["JSONDATA"] . "connection.json";
    $json_mysql = file_get_contents($json_file);
    $json_parsed = json_decode($json_file,true,250);
    foreach($json_parsed as $key => $value) {
        $this->connectionParams[$key] = $value;
    }
}

My goal is to fill this array $this->connectionParams with data extracted from the JSON file.

Not here, unfortunately, @Jessica. I get a NULL, like if the JSON were malformed. — Edvaldo Silva de Almeida Jr
– Edvaldo Silva de Almeida Jr, Commented Jul 30, 2015 at 3:17
I notice you are trying to decode the filename @EdvaldoAlmeidaJr. not the file content. — frz3993
– frz3993, Commented Jul 30, 2015 at 3:34

frz3993 · Accepted Answer · 2015-07-30 03:39:13Z

1

I notice that you are trying to decode the filename instead of the content.

$json_file = $this->system_paths["JSONDATA"] . "connection.json";
$json_parsed = json_decode($json_file,true,250);

Shouldn't it be

$json_parsed = json_decode($json_mysql, true, 250);

answered Jul 30, 2015 at 3:39

frz3993

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