How to convert variable value into jQuery object?

Question

For some reason I need to convert jquery variable value into object.

$("input[type=text]").on("keyup", function () {
    var target = this.id; //outputs 'subject'
    //how to convert here?
    var targetItem = $("#subject");//originally like this.
    //I tried something like below
    //var targetItem = $("#+target+");
    alert(targetItem);
});

All I'm trying to do is , changing the word in this: $("#subject") with whatever value of variable 'target'.

just one doubt. Why do you need this code? because object which you will get is same one you get by simply using this — Amit.rk3
– Amit.rk3, Commented Jul 31, 2015 at 10:53
Provide minimalistic sample to replicate your issue because your posted code doesn't make sense or maybe your example sample isn't relevant to your use case issue — A. Wolff
– A. Wolff, Commented Jul 31, 2015 at 10:55

Sougata Bose · Accepted Answer · 2015-07-31 10:56:33Z

2

Use this -

var targetItem = $(this); // Will always hold the current element object

And for the code you are using it should be -

var targetItem = $("#" + target);

target is a variable. "#+target+" will be treated as #+target+ not #subject (in your case)

edited Jul 31, 2015 at 10:56

answered Jul 31, 2015 at 10:54

Sougata Bose

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3 Comments

sabithpocker Over a year ago

You can also please correct the way he is trying to concatenate strings

Sougata Bose Over a year ago

@sabithpocker :) Thanks.

Sougata Bose Over a year ago

@sabithpocker You Are Welcome. ;)

Sudharsan S · Accepted Answer · 2015-07-31 10:50:32Z

1

Simply like

var target = this.id;
var targetItem = $("#"+target);

answered Jul 31, 2015 at 10:50

Sudharsan S

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4 Comments

A. Wolff Over a year ago

But because IDs must be unique on document context, it doesn't make sense

Balachandran Over a year ago

@soosmca No need id value ,You can use this directly $(this)

Sudharsan S Over a year ago

@Balachandran - I am just notices what mistake the OP had done

Balachandran Over a year ago

That is good but i gave suggestion you can wrap this with $ directly

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