Creating an exact json file by using php

Question

I need to write the following output in PHP:

var data = { "count": 1, "elements": [{"id": 1, "title": "title123", "url": "x123.php", "file_url": "x124.jpg"}]}

I have tried:

$txt = 'var data = { "count": 1,"elements": ';
$txt = $txt + '[{"id": 1, "title": "title123", "url": "x123.php", "file_url": "x124.jpg"}';
    $something = json_encode($txt);
    echo $something;
    //
    $something = print_r($txt);
    echo $something;
    //
    $something = print_r(json_decode($txt));
    echo $something;
    //
    ob_start;
    var_dump($txt);
    $something = ob_get_contents();
    ob_end_clean();
    echo $something;

I also have tried this:

$txt = '?var ?data ?= { "count": 1,"elements":';
for ($x = 0; $x <= strlen($txt); $x++) {
    $neso = substr($txt,$x,1);
    if ($neso != "?") {
    echo "+" + $neso + "+" + $x;
    }
}

Unfortunately I can not get any solution. All I get is 0 (zero) or 1 (one).

How can I get this output?

Viral · Accepted Answer · 2015-07-31 14:30:09Z

4

That's not how you generate json. PHP has absolutely NO clue what Javascript is - it's just plain text as far as PHP is concerned. When you do your $txt = 'var...', and encode that, you're producing a json representation of the STRING you produced in php, which means your json will become

"var data = {\"count\": etc...}"

and now the JSON you ALREADY had in there is escaped, and no longer json - it's just a plaintext string.

What you want is something more like:

$php_array = array(
   'count' => 1,
   'elements' => array(
       array('id' => 1, 'title' => etc...)
   )
)

$javascript = 'var txt = ' . json_encode($php_array) . ';';

Note that your echo "+" + $neso + "+" + $x; is utterly useless. + in PHP does mathematical addition. You're trying to do string concatenation, for which the operator is ..

edited Jul 31, 2015 at 14:30

Viral

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answered Jul 31, 2015 at 14:25

Marc B

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1 Comment

Viral Over a year ago

Welcome and, Well i must say thanks to you for your service on SO sir. @MarcB

André Tzermias · Accepted Answer · 2017-04-29 16:06:06Z

2

Learn about the structure of arrays, objects, and how the same thing is written in JSON.

To create a real json with PHP, the best way would be the following:

create an array with the actual data
json encode it
pass it on

What will then be "echoed" if you try, will be the contents inside the first {}.

I would start by doing:

$data = array(
'count' => 1,
'elements' => array(
            'id' => 1,
            'title' => 'title123',
            'url' => 'x123.php',
            'file_url' => 'x124.jpg',
            ),
);

then: echo json_encode($data); or return $json_encode($data), to pass the data on.

edited Apr 29, 2017 at 16:06

answered Jul 31, 2015 at 14:28

André Tzermias

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