[{"id":1,"name":"John"},{"id":2,"name":"James"},{"id":3,"name":"Alex"}]
$.grep(Arr.nameList, function(e){
return e.id != 1;
});
console.log(Arr.nameList);
I expect to get 2 array returning back with John discard but I still get them all back, what's wrong with my $.grep above?
jQuery.grep Description: Finds the elements of an array which satisfy a filter function. The original array is not affected.
.nameList you don't have to add anything just your array Arr.Replace :
$.grep(Arr.nameList , function(e){
return e.id != 1;
});
By :
var result = $.grep(Arr , function(e){
return e.id != 1;
});
You can find the result of grep :
console.log(result);
Take a look at Working fiddle.
Arr object ... structure of which is not knownnamelist based on unknown information. Arr could be a big object with lots of properties$.grep() returns a new filtered array and does not affect the original array.
Try :
var filteredArray = $.grep(Arr.nameList, function(e){
return e.id != 1;
});
console.log(filteredArray);
What you were doing was creating a new filtered array but ignoring it and inspecting the original un-affected array
Reference: $.grep() docs
