java.lang.ArrayIndexOutOfBoundsException looping?

Question

This is a loop inside other loops, s[] is a char array. By this I am moving char step by step.what should I do for correcting it

for(k=j; s[k]!='\0' ;k++)    
{                         
   s[k]=s[k+1];                          
}

both statements s[k]!='\0' and s[k+1] will eventually throw your exception — SomeJavaGuy
– SomeJavaGuy, Commented Aug 3, 2015 at 9:46
Possible duplicate of What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? — Alex Celeste
– Alex Celeste, Commented Oct 18, 2015 at 16:24

Eran · Accepted Answer · 2015-08-03 09:47:32Z

1

You should realize that arrays in Java have a length, so your null terminated check is wrong. Since you access the k+1'th element inside the loop, k must not go beyond s.length - 2.

for(k=j; k < s.length - 1 ;k++)
{ 
    s[k]=s[k+1];   
}

answered Aug 3, 2015 at 9:47

Eran

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