php - how to loop through values of one specific key in an associative array?

Question

I am new to php, I have an associative array like this

$arr['Joe'] = "test1";
$arr['Joe'] = "test2";
$arr['Joe'] = "test3";

how do I loop through all the values test1, test2, test3 of this specific key Joe?

I tried this

foreach ($arr as $key => $value) {
    echo $value;
}

and this

foreach ($arr as $key => $value) {
    echo $arr [$key]['Joe'];
}

But nothing ! Please help me?

You can't have multiple keys with the same name. In your case Joe will always be test3. — Andrei
– Andrei, Commented Aug 3, 2015 at 15:01
oh! I didn't know that, is there any other ways to hold multiple values in an associative array? — Maria Bernal
– Maria Bernal, Commented Aug 3, 2015 at 15:05
you are setting the values wrong to the array, do this instead $arr['Joe'][0] = "test1"; etc.. — Sayed
– Sayed, Commented Aug 3, 2015 at 15:09

Emil · Accepted Answer · 2015-08-03 15:06:10Z

4

I think this is what you want:

<?php

$arr['Joe'][] = "test1";
$arr['Joe'][] = "test2";
$arr['Joe'][] = "test3";

foreach ($arr['Joe'] as $key => $value) {
    echo $value;
}
?>

By adding [] after ['Joe'] the values will be saved like this:

(
    [Joe] => Array
        (
            [0] => test1
            [1] => test2
            [2] => test3
        )

)

answered Aug 3, 2015 at 15:06

Emil

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Comments

Andrew · Accepted Answer · 2015-08-03 15:12:04Z

0

To hold multiple values in an associative array they each need to be unique. eg.

$arr['Joe1'] = "test1";
$arr['Joe2'] = "test2";
$arr['Joe3'] = "test3";

and then

foreach ($arr as $value) {
    echo $value;
}

answered Aug 3, 2015 at 15:12

Andrew

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