PHP how to assign new value to object without updating previous value

Question

This is the code for an object:

$a = new stdClass();
$a->value = 'key';
$array[] = $a;
$array[] = $a;
$a->value = 'key2';
$array[] = $a;
print_r($array);

and this is the code for an array

$a = array("value" => "key");
$array[] = $a;
$array[] = $a;
$a['value'] = 'key2';
$array[] = $a;
print_r($array);

output for object:

Array
(
    [0] => stdClass Object
        (
            [value] => key2
        )

    [1] => stdClass Object
        (
            [value] => key2
        )

    [2] => stdClass Object
        (
            [value] => key2
        )

)

output for array:

Array
(
    [0] => Array
        (
            [value] => key
        )

    [1] => Array
        (
            [value] => key
        )

    [2] => Array
        (
            [value] => key2
        )

)

When $a is an Object, it updates the value already in $array to key2 but when $ais an array it only updates the last value. How can I get the object to behave like the array and only update the last value?

Thank you.

possible duplicate of How do I create a copy of an object in PHP? — kamal pal
– kamal pal, Commented Aug 3, 2015 at 16:28

Rizier123 · Accepted Answer · 2015-08-03 16:22:43Z

2

PHP objects are automatically passed by reference, so if you update the last one it will update everything. So just use clone, to clone your object, e.g.

$array[] = clone $a;
         //^^^^^ See here

answered Aug 3, 2015 at 16:22

Rizier123

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