Submit button not working in Selenium webdriver

Question

When I launch ChromeDriver or IEDriver and click the submit button (manually and automatically), it does not send the inputs. It works outside of webdriver though, I can click the submit button and send the inputs but in webdriver, it doesn't seem do anything. Is this something wrong with webdriver?

Thanks.

Note: The selenium version is the latest 2.47.0 along with chrome and chromedriver. I can't provide the link to the webpage since its a private server. Here is the code for the button

<span id="button-1429-btnInnerEl" class="x-btn-inner x-btn-inner-center" unselectable="on">Submit All</span>

Can you add more details like selenium version.ie version,chromeversion, iedriverserver version,chromedriver version, And is it possible to provide the link for the webpage.or html code for the button. — Madhan
– Madhan, Commented Aug 5, 2015 at 16:20
The selenium version is the latest 2.47.0 along with chrome and chromedriver. I can't provide the link to the webpage since its a private server. Here is the code for the button...<span id="button-1429-btnInnerEl" class="x-btn-inner x-btn-inner-center" unselectable="on">Submit All</span>.. Thank you — ihossain
– ihossain, Commented Aug 5, 2015 at 16:34
are you using sencha extjs application.If yes which version of extJS — Madhan
– Madhan, Commented Aug 5, 2015 at 16:39

danielepolencic · Accepted Answer · 2015-11-13 11:30:20Z

11

Having the same issue. Using element.sendKeys(Keys.ENTER) solves it for me.

answered Nov 13, 2015 at 11:30

danielepolencic

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Jaffar Ahamed · Accepted Answer · 2019-12-29 10:42:15Z

2

It will solve, Here I'm using python language. First, you need to import Keys and the following code will help you.

from selenium.webdriver.common.keys import Keys
login_btn=driver.find_element_by_id('button-1429-btnInnerEl').send_keys(Keys.ENTER)

answered Dec 29, 2019 at 10:42

Jaffar Ahamed

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David Buck · Accepted Answer · 2021-04-22 05:45:57Z

1

Solution:-

step 1. import org.openqa.selenium.Keys;

step 2. driver.element.sendKeys(Keys.ENTER);

edited Apr 22, 2021 at 5:45

David Buck

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answered Apr 21, 2021 at 7:57

Mayur Kodhe

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silhouette hustler · Accepted Answer · 2015-08-12 15:24:50Z

0

Try to click it with javaScript:

var element = driver.FindElement(By.Xpath("//span[contains(@id, 'button-1429')]"));

 var js = (IJavaScriptExecutor) driver;
 js.ExecuteScript("arguments[0].click()", element);

answered Aug 12, 2015 at 15:24

silhouette hustler

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7 Comments

ihossain Over a year ago

I tried that but it doesn't work for me. Thanks though

silhouette hustler Over a year ago

what exception you are getting?

ihossain Over a year ago

there is no exception, the test passes but it doesn't actually submit anything. When I look at the test, I can clearly see selenium interacting with the button but it doesn't actually submit anything.

silhouette hustler Over a year ago

Did you inspect the element and typed 'Submit All' in search box to double check if there is only one element with that text. Because if it is not that might be one of the reasons why the button is not being clicked?

ihossain Over a year ago

I'm only seeing one the element show when I search using the xpath in the console. Good point though. I'm thinking it may have something to do with extjs 4?

|

David Buck · Accepted Answer · 2021-04-22 05:46:09Z

0

You can try this:-

driver.findElement(By.xpath("//*[contains(text(),'Submit All')]")).click();

edited Apr 22, 2021 at 5:46

David Buck

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answered Sep 11, 2019 at 9:43

rajpal yadav

1

2 Comments

Shanteshwar Inde Over a year ago

can you please add proper explanation for better understanding

rajpal yadav Over a year ago

I have used customized xpath which finds an element which contains Text "Submit All" and then click on it. If you want xpath with id or name please share the code of the button, which will be definitely starting with <button> or <input> tags.

AmitKS · Accepted Answer · 2021-04-24 10:30:45Z

0

You can use Action Class. Might be Button is in Displayed false.

IWebElement button = driver.FindElement(By.Id("submit")); // locate the button
Actions action = new Actions(driver);
action.MoveToElement(button).Click().Perform();

edited Apr 24, 2021 at 10:30

answered Apr 21, 2021 at 17:34

AmitKS

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