In array not matching with array

Question

$blockon2 = array("opi-infinite-shine", "opi-gel", "cnd-vinylux", "opi");

var_dump(in_array(array("opi-infinite-shine", "opi-gel"), $blockon2, true));
// returns false

Someone has some idea of why it's returning false? Thanks!

It searchs for the exactly matching, so to return true is necessary an array inside $blockon2 with the needle ($blockon2[]= array("opi-infinite-shine", "opi-gel"))

I read a comment on stack overflow saying to try this. but it does not work with or without the cast. — flowers for martians
– flowers for martians, Commented Aug 7, 2015 at 12:41
check the values of the first array, to see if any of them is on the second array, returning true or false — flowers for martians
– flowers for martians, Commented Aug 7, 2015 at 13:11

miller · Accepted Answer · 2015-08-07 13:23:36Z

4

You can use array_diff instead:

$blockon2 = array("opi-infinite-shine", "opi-gel", "cnd-vinylux", "opi");

var_dump(!(bool)array_diff(array("opi-infinite-shine", "opi-gel"), $blockon2));

It will return true if all array entries present in original array

Or if you need to check if any of values exist try array_intersect:

$blockon2 = array("opi-infinite-shine", "opi-gel", "cnd-vinylux", "opi");

var_dump((bool)array_intersect(array("opi-infinite-shine", "opi-gel"), $blockon2));

edited Aug 7, 2015 at 13:23

answered Aug 7, 2015 at 12:49

miller

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8 Comments

Federkun Over a year ago

You can't use array as needle in in_array - untrue, var_dump(in_array(array(1,2), array(array(1,2),array(3,4)), true)); is true

Script47 Over a year ago

Quoted from PHP.net Example #3 in_array() with an array as needle. You can use array as needle.

miller Over a year ago

Ok, my bad. Updated my answer

flowers for martians Over a year ago

I just need 1 entry to be present, not all of them.

flowers for martians Over a year ago

You are right, I should use array_diff, since in array looks for the exactly match, so I can't give different values for the needle.

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