How Array work (Javascript)?

Question

I have a array is product

product[1][...]
product[2][...]
...

And I have a other array is hold.

My command:

hold['product'] = product;

for(i in product){
    delete product[i];
}

for(i in hold['product']){
    alert(i);
}

And Nothing happen. hold array doesn't have any element when I delete element of product array?

GPicazo · Accepted Answer · 2015-08-10 04:42:05Z

2

That is expected behavior. Complex types such as arrays are passed by reference in JavaScript. So when you assign an array to another variable, you are really assigning the reference. In order to avoid it, you should assign a copy of the original.

Try:

hold['product'] = product.slice(0);

edited Aug 10, 2015 at 4:42

answered Aug 10, 2015 at 4:37

GPicazo

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Comments

RIYAJ KHAN · Accepted Answer · 2015-08-10 04:41:34Z

0

try this one

var hold['product'] = product.slice();

It will create new copy of array on heap memory.So both array have their own copy

for more please check this one slice

answered Aug 10, 2015 at 4:41

RIYAJ KHAN

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