I've got 3 arrays
var arr1 = ["2", "3", "1"],
arr2 = ["x", "y", "z"],
arr3 = [];
how can I call items from arr2 into arr3 according to the arr1 number order? Example:
arr3 = ["y", "z", "x"];
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have you try it before posting ????dom– dom2015-08-11 05:20:16 +00:00Commented Aug 11, 2015 at 5:20
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3 Answers
For 0 indexed array numbers
for(var i = 0; i < arr1.length; i++){
arr3.push(arr2[arr1[i]])
}
Or since you are using 1 indexed array
for(var i = 0; i < arr1.length; i++){
arr3.push(arr2[arr1[i] - 1])
}
1 Comment
DGS
You probably could, I don't think you need to though since this solution seems easy enough
You can try something like this:
var arr1 = ["2", "3", "1"],
arr2 = ["x", "y", "z"],
arr3 = [];
arr3=arr1.map(function(i){return arr2[i-1]});
console.log(arr3)
Comments
If the values of arr1 do not correspond with keys, like if arr1 = [50, 4, -2, 999], then here is a convoluted answer:
arr1.map(function(val, key){ return [val, key] })
.sort(function(a,b){ return a[0]-b[0] })
.map(function(a){ return arr2[a[1]] })
1 Comment
jack blank
i get ` ["z", "y", "x", undefined]` i like your methodology but it should be
["y", "z", "x"]. did you get the same results as me. if not can you fix the answer.