Js regex test except string

Question

i have this list:

tests.skills
tests.instructions
tests.something

I want to test if the given string include any of the last two but not the first one, so i tried this:

 var str = 'tests.instructions';
 if( /tests\.[^skills].+/ig.test(str) ) {
      console.log(1);
  }

But it does not work, how can i test this?

ndnenkov · Accepted Answer · 2015-08-11 12:48:41Z

2

/tests\.(?!skills).+/

The set negation [^x] will try to match a character that is not x. What [^skills] actually means is match a single character, which is not s or k or i or l or l or s.

Instead a negative lookahead (?!sequence) will do the job.

edited Aug 11, 2015 at 12:48

answered Aug 11, 2015 at 12:44

ndnenkov

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2 Comments

user233232 Over a year ago

You can explain what your regex do?

ndnenkov Over a year ago

@user233232, I guess you already know everything except for the (?!) part. It is called a negative lookahead. Basically, what it does is matches an empty string if what follows in the current position is not skills and fails the entire match otherwise.

user4227915 · Accepted Answer · 2015-08-11 12:48:27Z

1

You can also try:

tests\.(?:instructions|something)

It means: search for tests. text which is followed by instructions or something.

Regex live here.

answered Aug 11, 2015 at 12:48

user4227915

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