Parse array in jquery from ajax request

Question

I am having the hardest time parsing the response from an ajax request correctly. I have an ajax request that gets back a json array, all I need to do is parse it correctly so I get my two values out.

On the php side, I create the array like so:

while($row = $result->fetch_assoc()) {

            $response[]=array("value" => $row["uid"], "text" => $row["value"]);
        }

My array in PHP looks like this when I print_r:

Array ( [0] => Array ( [value] => 6 [text] => 40 ) [1] => Array ( [value] => 7 [text] => 48 ) )

I then json_encode that array and send it back via ajax. Here is my ajax call:

 $.ajax({
                type: 'GET',
                url: 'ajax.php?s='+selection,
                dataType: 'json',                        
                success: function (data) {
                        $.each( data, function( intValue, currentElement ) {
                                $.each(currentElement, function( key, value ) {
                                    console.log(key);
                                    console.log(value);
                                });
                        });

                }
        });

I would have thought console.log(key) would show 6 and console.log(value) would show 40 but instead I get:

value
6
text
40
value
7
text
48

I really need help just getting 6 and 40 then 7 and 48 (based on array provided).

I have tried a bunch of ways, nothing seems to work.

Sevle · Accepted Answer · 2016-02-28 11:10:49Z

1

You can do something like this using single $.each() , and object property can access like object.property or object\["property"\]

var data = [{
  value: 6,
  text: 40
}, {
  value: 7,
  text: 48
}];
$.each(data, function(i, v) {
  document.write(v.value);
  document.write(v.text);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

edited Feb 28, 2016 at 11:10

Sevle

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answered Aug 12, 2015 at 17:35

Pranav C Balan

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2 Comments

Jason Over a year ago

I added to my question how I create my array, am I creating it wrong?

Pranav C Balan Over a year ago

@Jason : I couldn't see anything wrong in that. You can use single $.each to iterate

dcass · Accepted Answer · 2015-08-12 17:36:19Z

0

This works for me:

 $.ajax({
                    url: URL,
                    dataType: "text",
                    async: true,
                    cache: false,
                    contentType: "application/x-www-form-urlencoded; charset=UTF-8",
                    crossDomain: true,
                    success: function (data2) {

                        json_obj2 = $.parseJSON(data2);

answered Aug 12, 2015 at 17:36

dcass

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Comments

charlietfl · Accepted Answer · 2015-08-12 17:45:34Z

0

You have an extra each loop that isn't needed

Your javascript data looks like:

[{"value" : 6, "text" : 40}, {"value" : 7, "text" : 48}]

So in first each loop intVal will be index of array and currentElement will be each object instance in the array

The object instance looks like:

{"value" : 6, "text" : 40}

So currentElement.value and currentElement.text are what you are looking for

$.each( data, function( intValue, currentElement ) {
      console.log(currentElement.value);
});

edited Aug 12, 2015 at 17:45

answered Aug 12, 2015 at 17:40

charlietfl

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Comments

CasualT · Accepted Answer · 2015-08-12 19:52:30Z

0

Perhaps, change the php side to be:

$response[$row["uid"]] = $row["value"]

answered Aug 12, 2015 at 19:52

CasualT

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