Bash script to check a specific php process is running?

Question

I am running websocket server with the nohup command like below.

nohup php -q chat-server.php > ratchet_ws.log &

But it stop working after few hours.So i have created a bash script like below

#!/bin/bash
while true
do
if pgrep php > /dev/null
then
    echo  "Running" 
else
   cd /..path../
   nohup php -q chat-server.php > ratchet_ws.log &
fi
sleep 1;
done

Then i run the script with below command like below.

nohup sh chk_process.sh > chk_process.log &

The work of the above script if to check my chat-server.php is running or not if it is not running then it will start it again.

if pgrep php > /dev/null

But this line is checking any php process is running or not .But i want it to check only my chat-server.php.

Please be aware that you are checking if a process is running, but a running process isn't always a healthy process nor a responsive process. I would recommend trying to connect to the service as well. — Myst
– Myst, Commented Aug 13, 2015 at 6:59

user258367 · Accepted Answer · 2015-08-13 05:39:24Z

1

you can use pgrep -f or pgrep -x option.

entry from man page

-f The pattern is normally only matched against the process name. When -f is set, the full command line is used.
-x Only match processes whose name (or command line if -f is specified) exactly match the pattern.

answered Aug 13, 2015 at 5:39

user258367

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3 Comments

Pradeepta Over a year ago

Thanks @user258367.Can you give an example.

user258367 Over a year ago

pgrep -f "$COMMAND LINE" or pgrep -x $processname. you can check commandLine or processname by running command ps -x in your session.

Pradeepta Over a year ago

Thanks @user258367.I have used "if pgrep -f php -q chat-server.php > /dev/null" its working now.

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