Javascript order in array

Question

I am trying to order an array. I tried following code:

var groupUserCounter=[];
groupUserCounter["g1"]=1;
groupUserCounter["g2"]=2;
groupUserCounter["g3"]=3;

console.log(groupUserCounter.sort(function(a, b){return b-a}));

It returned:

Array [  ]

How can I do descending order?

You've added some properties to your array object. Array Indices should be numbers. — Teemu
– Teemu, Commented Aug 14, 2015 at 9:41
groupUserCounter.push() instead of assigning the properties. — Shilly
– Shilly, Commented Aug 14, 2015 at 9:42
How is that? Those properties are not sortable. Please read how JS arrays work. If you need key-value pairs, you have to use an object. That's not sortable though. — Teemu
– Teemu, Commented Aug 14, 2015 at 9:44

Shilly · Accepted Answer · 2015-08-14 09:49:58Z

5

Your issue is that you're trying to mix arrays and objects in a way they don't work. Try pushing objects into an array like this:

var groupUserCounter = [];
groupUserCounter.push({'g1':1});
groupUserCounter.push({'g2':2});
groupUserCounter.push({'g3':3});
groupUserCounter.sort(function(a, b){
    var propA = Object.keys(a)[0],
        propB = Object.keys(b)[0];
    return b[propB] - a[propA];
});

Or just use an object altogether and write a sort function based around Object.keys(yourKeyValueObject) as RGraham kindly demonstrates below.

edited Aug 14, 2015 at 9:49

answered Aug 14, 2015 at 9:48

Shilly

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1 Comment

Shilly Over a year ago

It pushes objects (key/value pair) to an array, so you can use the sort function of arrays. It then checks the first property of each object in the array and returns the difference between the value of the property in b and the property in a.

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