PHP - How to check if array contains a value by index?

Question

Example: $array = ['name', 'address'];

It contains $array[0] and $array[1] only.

If i try $array[2] i should receive an error.

So, i want to avoid these errors by checking it in a if statement. How can i check if an array contains a value in certain index?

hellcode · Accepted Answer · 2015-08-15 16:14:58Z

1

You can use the isset function:

if(isset($array[2])) {

answered Aug 15, 2015 at 16:14

hellcode

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Comments

mtszkw · Accepted Answer · 2015-08-15 17:00:29Z

0

The second way to make it work is check how big is an array:

if(count($array) >= 3) { ... } // three or more elements: 0, 1, 2...

answered Aug 15, 2015 at 17:00

mtszkw

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