HTML variable and text value transfer to PHP/javascript?

Question

So this is what i have in html:

    <p><br><form name="edit" method="post">
        <div><select name="Edi" id ="Edi" >
        <option selected="selected">Select</option>
        <option value="1.php">Apple</option>
        <option value="1.php">Bannana</option>
        <option value="2.php">Carrot</option>
        </select>
            <input onclick="return Edit();" type="submit" value="Edit"/></div>
    </form>

here is the corresponding javascript:

function Edit(){
    if(document.forms['edit'].Edi.value == "Select")
        {
            alert("Please Select Edit Field");
            return false;
        }
    else
    {
        window.open(Edi.options[Edi.selectedIndex].value);
        return true;
    }
}

Here is my problem. As you can see both my option Apple, and Bannana open the same php page. I want that. But i also want a variable in PHP that can store Apple/Bannana depending which was chosen in dropdown. I tried this in PHP and it did not work.

 $Table = $_POST['Edi'];

I know i can create a different PHP page for Apple(1.php) and Bannana(3.php). But in my program creating a page will just be duplicated code. (Apple and bannana just decide which table to store in). Also, i might be adding more options in the future, so i dont want to keep copying code.

What i came up with is putting the variable in javascript, but then tranfering to PHP is not possible. So I decided with creating extra layer rather than creating copied pages. (1 selected-shows apple, bananna) (2 selected-shows carrot). I can do this.

But is this the most efficient way of doing this?

It depends on the context. You might just add Apple/Banana in GET parameter. (Simplest way to do it but maybe not most efficient, secure, good looking, etc.) — user3849602
– user3849602, Commented Aug 19, 2015 at 16:44

showdev · Accepted Answer · 2015-08-19 16:53:24Z

1

You can use PHP's $_GET array to access URL parameters.

For example:

<option value="1.php?table=apple">Apple</option>
<option value="1.php?table=banana">Banana</option>

And your PHP:

$table = $_GET['table'];

If the variable could be missing, you can provide a default value by using PHP's ternary operator:

$table = isset($_GET['table']) ? $_GET['table'] : 'apple';

edited Aug 19, 2015 at 16:53

answered Aug 19, 2015 at 16:46

showdev

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USER420 Over a year ago

What i was looking for. Works like a charm!

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