How can I auto increment id column based on the 0 to max (int) value on the price column.
Lets assume that price is ASC, I want the id = 1 increment to start at the $0 mark. What would I have to edit for this code ALTER TABLE table AUTO_INCREMENT = 1 ?
id | price | other columns
1 | 9
2 | 1
3 | 2
4 | 5
into
id | price | other columns
1 | 1
2 | 2
3 | 5
4 | 9
sorry, you must send 2 Querys. The first to set rhe Variable nr to 0 and then the update statement
SET @nr:=0;
UPDATE your_table_name t
SET t.id = @nr:=@nr+1
ORDER BY t.price ASC;
A easy Way ist to create a new table with one column more with autoincrement.
intert into newtable select '',o.* from oldtable o order by o.price asc;
Then they insert all row in the right order from price in the new table.
id column based on the price columnif you only want to have a row with rownumber, so you can do it like this:
SELECT @nr:=@nr+1 AS id,c.* FROM mytable c, (SELECT @nr:=0) tmp;
f_id how would I be able to auto increment the new column based on the price asc column? And if this is possible would I be able to delete old f_id column and create a new f_id column with auto increment whenever I update the db?the feld x is NOT autoincrement. its only a non uniqe index
SET @nr:=0;
UPDATE newtable n SET n.x = @nr:=@nr+1 ORDER BY n.price ASC;