Compare all array values with a single string - PHP

Question

Is there a short way to write this? Like below:

<?php

$true=1;
$false=0;

$valid = array (
                "part1" => $true,
                "part2" => $true,
                "part3" => $true
);

if($valid == $true){
echo "All the values are True!";
}else{
echo "At list one of the values is False";
}

?>

Instead of this:

 <?php

    if($valid['part1'] == $true && $valid['part2'] == $true && $valid['part3'] == $true{
    echo "All the values are True!";
    }else{
    echo "At list one of the values is False";
    }

    ?>

I have tried writing it as showed in the first example but it doesn't work

if (count(array_filter($valid)) == count($valid)) { echo 'All the values are Truthy'; } else { echo 'at least one of the values is falsey'; } — Mark Baker
– Mark Baker, Commented Aug 25, 2015 at 17:24
array_filter is probably slower than the array_unique answer below. — twentylemon
– twentylemon, Commented Aug 25, 2015 at 17:26
@mark use array_unique and equal it to 1 will make the code much faster and much less code is used in general — Buddhi741
– Buddhi741, Commented Aug 25, 2015 at 17:26
@QuakeCore gave the best answer though must admit i didnt see that approach — Buddhi741
– Buddhi741, Commented Aug 25, 2015 at 17:28

QuakeCore · Accepted Answer · 2015-08-25 17:26:26Z

4

if(!in_array($false,$valid){
echo "All the values are True!";
}else{
echo "At list one of the values is False";
}

answered Aug 25, 2015 at 17:26

QuakeCore

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Comments

rjdown · Accepted Answer · 2015-08-25 17:26:49Z

1

You can use array_keys' second option to search for values matching your variable, and compare the number of results against the total number of elements in your array:

if (count(array_keys($valid, $true)) == count($valid)) {
    echo "All the values are True!";
} else {
    echo "At leastone of the values is False";
}

answered Aug 25, 2015 at 17:26

rjdown

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Comments

Buddhi741 · Accepted Answer · 2015-08-25 17:24:53Z

0

its an array not a variable you cant just === it

you will have to use

if (count(array_unique($allvalues)) === 1 && end($allvalues) === 'true') {
echo "All the values are True!";
}else{
echo "At list one of tha values is false";
}

answered Aug 25, 2015 at 17:24

Buddhi741

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Comments

Matiboux · Accepted Answer · 2015-08-25 17:34:02Z

0

You can do this with that:

$array = array(
    'key1' => true,
    'key2' => true,
    'key3' => true,
);

$status = true;
foreach($array as $key => $value) {
    if(!$value) {
        $status = false;
        break;
    }
}
if($status) {
    echo "All the values are True!";
}
else {
    echo "At list one of the values is False";
}

answered Aug 25, 2015 at 17:34

Matiboux

1128 bronze badges

2 Comments

Buddhi741 Over a year ago

not the best approach given you are skipping out on opportunities to do this way more efficiently. but this is still another approach to it

Matiboux Over a year ago

@BuddhiAbeyratne - True. After my post, I have see the others awnsers with in_array() and array_keys() but I like my way to to it. Always good to know how to do it without specials functions.

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