PHP Error: Call to undefined function saveimage

Question

<?php
    require('config.php');
    if(isset($_POST['upload'])){
        if(getimagesize($_FILES['image']['tmp_name'])==FALSE){
            $first_ul_status = "Please select an image";
        }else{
            $image = addslashes($_FILES['image']['tmp_name']);
            $name = addslashes($_FILES['image']['name']);
            $image = file_get_contents($image);
            $image = base64_encode($image);
            saveimage($name,$image);
        }
        function saveimage($name,$image){
            $first_ul_query = "UPDATE `users` SET `Photo Name`='$name',`Photo`='$image' WHERE `ID`='$UserSession'";
            $first_ul_result = mysql_query($first_ul_query);
            if($first_ul_result){
                $first_ul_status = "Image uploaded";
            }else{
                $first_ul_status = "Image not uploaded";
            }
        }
    }

?>

I just got this code from the web I don't remember where I got this code. But I have the video tutorial of this thats why I have this code right now. Last time this code is working to me but now my problem is that I cant call the saveimage($name,$image);

Can somebody help me out there? Thanks in advance pros :)

PC-CD Interactive Multimedia · Accepted Answer · 2015-08-26 11:39:39Z

3

Be sure your saveimage() function is declared when call that. Put the function forward in your code as you call!

edited Aug 26, 2015 at 11:39

answered Aug 26, 2015 at 11:34

PC-CD Interactive Multimedia

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Comments

Danyal Sandeelo · Accepted Answer · 2015-08-26 13:23:48Z

3

You added function within the script..I have fixed it..the function is out of the code now. It is an independent snippet now, you can call it now..

<?php
require('config.php');


 function saveimage($name,$image){
        $first_ul_query = "UPDATE `users` SET `Photo Name`='$name',`Photo`='$image' WHERE `ID`='$UserSession'";
        $first_ul_result = mysql_query($first_ul_query);
        if($first_ul_result){
            $first_ul_status = "Image uploaded";
        }else{
            $first_ul_status = "Image not uploaded";
        }
    }


if(isset($_POST['upload'])){
    if(getimagesize($_FILES['image']['tmp_name'])==FALSE){
        $first_ul_status = "Please select an image";
    }else{
        $image = addslashes($_FILES['image']['tmp_name']);
        $name = addslashes($_FILES['image']['name']);
        $image = file_get_contents($image);
        $image = base64_encode($image);
        saveimage($name,$image);
    }

}


 ?>

edited Aug 26, 2015 at 13:23

answered Aug 26, 2015 at 11:18

Danyal Sandeelo

12.4k10 gold badges57 silver badges90 bronze badges

7 Comments

Marverick Over a year ago

still cant Fatal error: Call to undefined function saveimage()

Danyal Sandeelo Over a year ago

a quick fix...replace the saveimage($name,$image); with the code within the function.. try then.

Marverick Over a year ago

still cant. i tried to remove and separate but nothing happen, still same error

Danyal Sandeelo Over a year ago

what the error..if you remove saveimage.,,it wont work

Marverick Over a year ago

no error but can't save if i'll remove the saveimage()

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