PHP JSON Object parsing

Question

I'm trying to parse a JSON object in PHP. My efforts have lead to ending up with this var_dump:

string(5) "Malta"
string(2) "mt"
string(11) "St Julian's"
string(5) "Malta"
string(2) "mt"
string(11) "St Julian's"

Now what I want is just to print "Malta". All efforts of trying have failed and I need a hint into what to do next. Any ideas of how i can go about this? Thanks

Trying to parse this part: "location":

{
"totalFound":2,
"content":[
{
"id":"a1d17bwqeqewqeqweaf-1e54-4861-92e1-8246baba11d6",
"title":"Developer",
"refNumber":"REFqweqwe4N",
"createdOn":"2015-08-28T11:10:07.000Z",
"updatedOn":"2015-08-28T13:19:59.000Z",
"location":{
"country":"Malta",
"countryCode":"mt",
"city":"St Julian's"
},
"status":"SOURCING",
"actions":{
"details":{
"url":"www.google.com",
"method":"GET"
}
}
}
],
"offset":0,
"limit":10
}

My code snippet:

$jfo = json_decode($data, TRUE);

foreach ($jfo['content'] as $category) {
if (isset($category['title']) != null) {
}
if (isset($category['location']) != null) {



    foreach ($category['location'] as $location){
        var_dump($location);
        print_r($location);

Looks more like the var_dump is inside a loop rather than of the decoded object? — Jonnix
– Jonnix, Commented Aug 28, 2015 at 15:43
Result of print_r: string(5) "Malta" Maltastring(2) "mt" mtstring(11) "St Julian's" St Julian'sstring(5) "Malta" Maltastring(2) "mt" mtstring(11) "St Julian's" St Julian's — progdoc
– progdoc, Commented Aug 28, 2015 at 15:45

Buddhi741 · Accepted Answer · 2015-08-28 16:00:12Z

1

try to echo $category['location']['country'] remove the for each on there its tying to loop your location array

edited Aug 28, 2015 at 16:00

answered Aug 28, 2015 at 15:54

Buddhi741

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1 Comment

progdoc Over a year ago

tried, didn't work - its only printing the first character

Michael · Accepted Answer · 2015-08-28 16:05:38Z

1

The issue is that you're iterating over each element in location, i.e. country, countryCode, and city.

This does what you need:

$jfo = json_decode($data, TRUE);

foreach ($jfo['content'] as $content)
{
  echo $content['location']['country'];
}

edited Aug 28, 2015 at 16:05

answered Aug 28, 2015 at 16:00

Michael

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