How to print duplicates in string array only once

If you're stuck only using primitive arrays, create a second array called something like uniques and each time you come across a new value, grow that array by adding the new value to it. As you iterate to each index in flowerPack, iterate through uniques to see if it already contains the current index's value. If so, do nothing, else add it. At the end, you can then print out the contents of uniques.

Since you've said you can't use any library classes, and want to stick with your basic approach, here's a slight alteration you can make to only print a given type of flower once. It also saves you on a little computation. Basically, have a secondary boolean array in which you track whether you've already printed data incorporating the flower at an index or not.

You've expressed through comments some uncertainty about booleans. A boolean is just a representation of true or false. An array is a way of holding multiple values of a single type together, with some order associated with the values. In my solution, the idea is that you have a second array where the index (the numeric value representing which item in the array you care about) of the boolean array is used to correspond to the index of the flower array. So the 0 item in the boolean array corresponds to the 0 item in the String array, the 1 item corresponds to the 1 item, the nth item to the nth item etc.

You can use this boolean array to represent whether you have printed the information about the type of flower at index n or not.

Note: Have removed the actual code of the solution in the interest of encouraging learning by figuring out the details yourself. Best of luck!

To keep your code the most untouched possible, I would create a new variable like this:

private static void displayFlowers(String flowerPack[]) {
    // TODO: Display only the unique flowers along with a count of any duplicates
    /*
     * For example it should say
     * Roses - 7
     * Daffodils - 3
     * Violets - 5
     */
    int isChecked[] = new int[flowerPack.length];

    for(int i = 0; i < flowerPack.length; i++) {
        int count = 0;    
        for(int j = 0; j < flowerPack.length; j++) {
            if(flowerPack[i].equals(flowerPack[j]))
            {
                count++;
                if(i!=j)isChecked[j] = 1;
            }
        }
    if(isChecked[i]==0)
        System.out.println(flowerPack[i] + " - " + count);
    }
  }

With the array: String []flowers = new String[]{"rose","sunflower","rose","rose","sunflower","daisy","daisy"};

It prints:

rose - 3 sunflower - 2 daisy - 2

Hope that helps!!

You want to only print each word once, and to do that without using a Set, you could make sure to only print the word the first time, or the last time, it occurs. Let's assume first:

• Loop thru words:
  • Check if word exists earlier in the list.
  • If it does not:
    • Count number of times word exists after in the list.
    • Print the word and the count (+1 since you didn't count first word itself).