Read param in symfony from plain php class

Question

I have a plain PHP class and I want to read one of the parameter from config.yml file. I dont have a container instance to read and get the param value. How can I achieve this in a plain PHP class? Important thing is that I can not make a service of my php class.

what is the question exactly, can you add an example, it is not clear — Nikos M.
– Nikos M., Commented Aug 31, 2015 at 13:50

Jovan Perovic · Accepted Answer · 2015-08-31 13:53:57Z

4

It's actually very easy, since YAML is component on it's own:

use Symfony\Component\Yaml\Exception\ParseException;
use Symfony\Component\Yaml\Parser;

$yaml = new Parser();

try {
    $yamlData = $yaml->parse(file_get_contents('/path/to/config.yml'));

    // adjust what you need to read here.
    $paramValue = $yamlData['your_key']['sub_key'];

} catch (ParseException $e) {
    printf("Unable to parse the YAML string: %s", $e->getMessage());
}

Source: Reading YAML Files

answered Aug 31, 2015 at 13:53

Jovan Perovic

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