How to pass tuple to a Matlab function from Python

Question

I have a Matlab function that I'm calling from a python script:

import matlab.engine

eng = matlab.engine.start_matlab()
t = (1,2,3)
z = eng.tstFnc(t)
print z

The function tstFnc is as follows:

function [ z ] = tstFnc( a, b, c )
z = a + b + c

This does not work, however, as Matlab receives one input instead of three. Could this be made to work?

Note: this is a simplified case of what I want to do. In the actual problem I have a variable number of lists that I pass into a Matlab function, which is interpreted in the Matlab function using varargin.

Try z = eng.tstFnc(*t) to apply the arguments instead of passing them as a tuple — Pyrce
– Pyrce, Commented Sep 2, 2015 at 17:05

Pyrce · Accepted Answer · 2015-09-02 17:50:45Z

3

As notes in the comments, the arguments need to be applied instead of passed as a tuple of length 1.

z = eng.tstFnc(*t)

This causes a call to tstFnc with len(t) arguments instead of a single tuple argument. Similarly you could just pass each argument individually.

z = eng.tstFnc(1, 2, 3)

edited Sep 2, 2015 at 17:50

answered Sep 2, 2015 at 17:10

Pyrce

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3 Comments

sodiumnitrate Over a year ago

I should add that t = (2,3) and z = eng.tstFnc(1, *t) works too, in case anyone is curious.

rayryeng Over a year ago

@sodiumnitrate - Yes, that's a standard Pythonic way of splitting up the tuple. BTW, I've already +1ed your question and this answer.

sodiumnitrate Over a year ago

@rayryeng Yeah, ok, I didn't know :) Thanks!

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