When i use : ps -o user,cmd My output is :
User CMD
0 in.telnetd
0 sh
0 processd
0 processe
0 in.telnetd
0 -sh
0 top
I want to get 2 row (which contains processd & processe) after i do grep command .
What i used :
1. ps -o user,cmd | grep "processd\|processe"
2. ps -o user,cmd | grep processd | grep processe
Am i using correct format to grep what i want or is it like i need to modify my query ?
one way would be:
ps -o user,cmd | grep "process[de]"
of course you might end up catching also lines like
0 /some/other/app --with --lots of arguments including also processe
to make sure you do not catch that, you should probably use awk.
You were looking for
ps -o user,cmd | egrep "processd|processe"
When I need to check logfiles, I use something similar:
interesting="keyword1"
interesting+="|key2
interesting+="|key3"
skip="garbage1"
skip+="|garb2"
skip+="|garb3"
grep "^20150909" logfile | egrep "${interesting}" | egrep -v "${skip}"
egrep and suggesting we use grep -E instead.[SOLVED]
After some trial and error i just got to know about -E option .
ps -o user,cmd | grep -E processd\|processe
grep-like commands: the regular grep (which uses normal regular expressions), fgrep or grep -F (which uses fix strings) and egrep or grep -E (extended grep, which makes it possible to combine different regular expressions).