ruby, evaluation multiple conditions in an array

Question

So maybe I have this all wrong, but I'm sure there is a way to do this, say I have a an if statement, that I want to return true if all the conditions in an array evaluate as true.

say I have this:

def real_visitor?(location, request, params)

  valid_location = [
    params['referrer'] == 'us',
    params['bot'] != 'googlebot',
    5 + 5 == 10 
  ]

  if valid_location
    return true
  else
    return false
  end
end

How would I evaluate each of the conditions in the array valid_location, some of those conditions in that array are just pseudocode.

Paige Ruten · Accepted Answer · 2010-07-14 23:48:00Z

4

Use Array#any? or Array#all?. It's like putting the || or && operator between all your conditions, but it doesn't do short-circuit evaluation, which is sometimes useful.

return valid_location.all?

You don't need the return keyword, by the way. I'd leave it out.

answered Jul 14, 2010 at 23:48

Paige Ruten

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3 Comments

Wayne Conrad Over a year ago

In MRI 1.8.7, all? and any? short-circuit: all? stops at the first falsy value; any? stops at the first truthy value.

Paige Ruten Over a year ago

Well an example of what I mean is that [puts("1"), puts("2")].all? would print both "1" and "2", but puts("1") && puts("2") would only print "1", even though the semantics are the same. The items in the array are being evaluated before all? is being called.

Wayne Conrad Over a year ago

That makes perfect sense. Thanks for the great explanation.

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