Is there any way to make local scope variable accessible in outer scope without creating an object or without using 'this'?
Say,
function foo(){
var bar = 10;
}
Any way to make variable 'bar' available outside function 'foo' scope?
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If you don't want that variable local to that function, define it outside the function...Andy– Andy2015-09-13 12:44:12 +00:00Commented Sep 13, 2015 at 12:44
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1It doesn't make much sense to me. Local scope is designed to be local why would you want it to be part of any other scope?MinusFour– MinusFour2015-09-13 12:46:04 +00:00Commented Sep 13, 2015 at 12:46
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It was an interview question, any way to make it available in the outer scope on some condition.nim007– nim0072015-09-13 12:49:03 +00:00Commented Sep 13, 2015 at 12:49
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1You can make it available to the outer scope but then it wouldn't be local anymore.MinusFour– MinusFour2015-09-13 12:50:42 +00:00Commented Sep 13, 2015 at 12:50
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5 Answers
No. Simply you can't. Scope is scope. If you want to access outside, make it declare outside and use it.
That's how things designed. I don't suggest any crappy way to make it possible.
Comments
Assign the value to a property of the window object:
function foo(){
window.bar = 10;
}
console.log(window.bar); //10
EDIT:
Since you can't accept his answer, then no - what you're asking for is impossible. Only solution is to declare the variable in the global scope, then initialize it later.
6 Comments
nim007
Looking for any answer without changing 'var bar = 10'. It was an interview question.
jonny
Then it's impossible...you'd have to assign that value to a variable already declared in the global scope...
Suresh Atta
@Nimmy Testing your confidence levels :) You should say NOT POSSIBLE sir ;)
nim007
@Suresh atta :) Yeah I did, but just wanted to check if I was right,
Andy
Actually, if this was an interview question, then @sᴜʀᴇsʜᴀᴛᴛᴀ's answer re is exactly what they were looking for. The important word here that you should explain and then enhance on is "scope", not just say that it's not possible. They're looking for someone who understands why and can explain it. So blah blah unlike other languages JavaScript has function scope rather than block scope and local variable aren't available outside their functions, although the new version of JS (ES2016 or whatever it's called now) also has block scope etc.
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You can't access local variable outside the function.
Following post might help you to understand scopes in more detail -
Comments
You can do something like this:
var myScopedVariables = function foo(){
var bar = 10;
return [bar];
}
console.log(myScopedVariables);
1 Comment
Jamesfo
This is the answer. Any value from within a function that should be accessed outside that function should be returned by that function. Simple as that.
function myFunction() {
myVar = 'Hello'; // global variable
}
myFunction();
console.log(myVar); // output: "Hello"
1 Comment
Community
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