I want to replace a portion of a string that matches a regex pattern.
I have the following regex pattern:
(.+?)@test\.(.+?)
And this is a string replacement pattern:
$1@hoge\.$2
How can I use them inside Swift code?
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1 Answer
In Swift, you can use stringByReplacingMatchesInString for a regex-based replace.
Here is a snippet showing how to use it:
let txt = "[email protected]"
let regex = NSRegularExpression(pattern: "([^@\\s]+)@test\\.(\\w+)", options:nil, error: nil)
let newString = regex!.stringByReplacingMatchesInString(txt, options: nil, range: NSMakeRange(0, count(txt)), withTemplate: "$1@hoge.$2")
println(newString)
Swift 4.2 update:
let txt = "[email protected]"
let regex = "([^@\\s]+)@test\\.(\\w+)"
let repl = "$1@hoge.$2"
print( txt.replacingOccurrences(of: regex, with: repl, options: [.regularExpression]) )
Note that I changed the regex to
([^@\\s]+)- matches 1 or more characters other than@or whitespace@- matches@literallytest\\.(\\w+)- matchestest.literally and then 1 or more alphanumeric character (\w+).
Note that in the replacement string, you do not need to escape the period.
answered Sep 16, 2015 at 11:14
Wiktor Stribiżew
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7 Comments
Sentry.co
I wrote a RegEx replace method that takes a closure: eon.codes/blog/2017/08/03/regex-replace-with-closure
Wiktor Stribiżew
@GitSync I do not think the current problem needs to be solved with a closure enabled regex. Still, that can be of help to others, sure.
Sentry.co
@WiktorStribiżew Totally agree that closure is overkill with this problem. But I couldn't find anything on stack or google about replacing with closures so I thought Id mention it.
Wiktor Stribiżew
@GitSync I think I have seen that somewhere. Maybe something similar. If I find it, I will post a comment.
Sentry.co
@WiktorStribiżew My implementation isn't perfect. I think accumulatively appending a string is faster than inPlace substring replace. But I had to move on. I made a note of it in the code for a future improvement opportunity.
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