xslt get parent element by another element value

Question

Im trying to get the parent node based of child element value

I want to do something like that get TransactionDetail element where SequenceNumber = 2

I tried to do it like that but im missing something...

 ancestor:://*[local-name()='SequenceNumber'][text()=2]

 //TransactionDetail[//SequenceNumber = 2]

this is the xml

<Root>
<biztalk_1>

    <body>
        <ActiveStore_SalesTransaction_1.70>

            <TransactionDetail>
                <SequenceNumber>2</SequenceNumber>

                <TransactionDetailGroup>
                    <Item>
                        <ItemID>22</ItemID>

                        <NonMerchandiseFlag>1</NonMerchandiseFlag>
                    </Item>
                </TransactionDetailGroup>
            </TransactionDetail>




        </ActiveStore_SalesTransaction_1.70>
    </body>
</biztalk_1>

Linga Murthy C S · Accepted Answer · 2015-09-17 01:10:04Z

1

Using name() is not a good practice. Instead, use the element name in the xpath as below:

//TransactionDetail[SequenceNumber = 2]

The xpath selects all the TransactionDetail elements with a child SequenceNumber with value 2 in the whole document.

And if you want TransactionDetail with any descendant SequenceNumber with value 2, use:

//TransactionDetail[.//SequenceNumber = 2]

Here, the .//SequenceNumber makes sure that only the current TransactionDetail's descendant SequenceNumber elements are checked.

answered Sep 17, 2015 at 1:10

Linga Murthy C S

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1 Comment

Linga Murthy C S Over a year ago

@MIkCode There could be many reasons for this. I'm pointing some here. 1. The processing is much faster(depending of the processor). Some processors may list all the descendants first (because of *), and then filter based on name(). 2. The Xpath is easy to write without name(). Moreover, there is no necessity for using name() in such xpaths unless you want to escape the namespaces.

Rudramuni TP · Accepted Answer · 2015-09-16 15:57:11Z

1

Try this:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Root">
    <Root>
        <xsl:copy-of select="descendant::*[name()='TransactionDetail']
                                                        [descendant::*[name()='SequenceNumber']='2']"/>
    </Root>
</xsl:template>

</xsl:stylesheet>

answered Sep 16, 2015 at 15:57

Rudramuni TP

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