C#, returning an array in a function

Question

I have a method that generates an array. I want to return this array so I can use it another method. Here is my code so far:

public static Array[] generateFirstArray(int seedValue)
{
    int[] firstArray = new int[20];
    Random randomNumber = new Random(seedValue);

    for (int i = 0; i < firstArray.Length; i++)
    {
        firstArray[i] = randomNumber.Next(0, 4);
    }

    return firstArray;
}

But when I run it, I get the following error:

Error 1 Cannot implicitly convert type 'int[]' to 'System.Array[]'

I tried to add [] after firstArray but still not working.

D Stanley · Accepted Answer · 2015-09-16 15:27:40Z

13

Your return type is currently an array of Array objects. Change your return type to an array of ints (int[]):

public static int[] generateFirstArray(int seedValue)

answered Sep 16, 2015 at 15:27

D Stanley

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Justin Lessard · Accepted Answer · 2015-09-16 15:28:12Z

6

The signature of your methods says you're trying to return an Array of Array (Array[]).

You want to return an int[] instead so just change your signature to

public static int[] generateFirstArray(int seedValue)

answered Sep 16, 2015 at 15:28

Justin Lessard

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AlwaysAProgrammer · Accepted Answer · 2015-09-16 15:40:02Z

0

the return type of your method must be int[] and not Array[]

Here is one more way of implementing it

int Min = 0;
int Max = 4;
Random randNum = new Random(seedValue);
int[] firstArray = Enumerable
                   .Repeat(0, 20)
                   .Select(i => randNum.Next(Min, Max))
                   .ToArray();
return firstArray;

answered Sep 16, 2015 at 15:40

AlwaysAProgrammer

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