C - How do you store a string with variables in it within an array?

Question

Because I know that

char array[STRING_ELEMENTS + 1][MAX_STRING_LENGTH + 1];

/*just for the first element*/
array[0] == ("this number: %d, and that number: %d\n", a, b);

probably makes me look disgusting. I would have no clue how else to do this though.

You mean the problem that you have to use MAX_STRING_LENGTH? — Superlokkus
– Superlokkus, Commented Sep 17, 2015 at 13:29
@ameyCU sorry I'm very new to this. What do you suggest I name it to? — Laefica
– Laefica, Commented Sep 17, 2015 at 13:31
@Laefica The problem is: If your string gets longer than MAX_STRING_LENGTH because of the variables, snprintf which you must use for a safe program, will truncate you string. — Superlokkus
– Superlokkus, Commented Sep 17, 2015 at 13:44

Paul R · Accepted Answer · 2015-09-19 20:35:21Z

4

You can't assign a string like this in C, but you can use snprintf:

snprintf(array[0], MAX_STRING_LENGTH, "this number: %d, and that number: %d\n", a, b);

(don't forget to #include <stdio.h> somewhere near the top of your program.)

answered Sep 17, 2015 at 13:29

Paul R

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1 Comment

and #include <stdio.h> (for snprintf(3) function) also.