Use the current namespace with pars_args() in the argparse package in Python3

Question

I am using the argparse module in Python3. The result of the parsed arguments are given back as a Namespace object. But I want to have them in the current namespace and not a different one.

#!/usr/bin/env python3
import argparse

parser = argparse.ArgumentParser(description='desc')
parser.add_argument('--profile', dest='profile_name', help='help')

# I need the magic here    
print( parser.parse_args(namespace=self) )
print(profile_name)

Is there a way to handle this? Or do I have to make it myself manually like this:

args = parser.parse_args()
profile_name = args.profile_name

hpaulj · Accepted Answer · 2015-09-18 19:08:22Z

You may be confusing 2 uses of 'namespace'.

One namespace is the dictionary that holds the variables of this module or function.

parser.parse_args() creates an argparse.Namespace object, and puts its values in it, using setattr. This class definition is pretty simple.

parser.parse_args(namespace=myNamespace) should work with any object that accepts the setattr, getattr and hasattr methods. A dictionary does not work.

If given a dictionary the first error I get is in

setattr(namespace, action.dest, default)
AttributeError: 'dict' object has no attribute 'checked'

Are you asking this because you want to put the argparse attributes directly in the local namespace dictionary?

You can convert a Namespace to a dictionary with vars(args). And you can add those items to another dictionary with update (e.g. locals().update(vars(args)) ).

Or if you have a function that takes **kwargs, you could use: foo(**vars(args)) to put those arguments into the function's namespace. This does a better job of localizing the change. It also lets you define the variables with the normal keyword syntax.

multivac · Accepted Answer · 2015-09-18 16:52:15Z

1

I do not recommend this since it can override previously defined variables, especially if all you want is avoid typing a couple of characters, but you can add variables to the global scope like this:

args = parser.parse_args()

for k, v in args.__dict__.items():
    globals()[k] = v
print(profile_name)

edited Sep 18, 2015 at 16:52

answered Sep 18, 2015 at 16:41

multivac

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