Javascript - Return in a function parameter another function

Question

What i'm trying to do might sound simple.

I just need to make a callback with another function Here is an example using jQuery.

(function ( $ ) {
    "use strict";
    var colors;

    colors = function(col){
        return col;
    };

    $(document).ready(function(){
        colors(function(){alert('Orange');});
    });
})(jQuery);

So when the document be ready, i need to send an alert that says 'Orange' but i want to do it by returning a function.

If you know another way to do it please let me know.

Strictly speaking, what you're asking to do is not possible. The way you make an alert popup happen is by calling the alert() function. — Pointy
– Pointy, Commented Sep 23, 2015 at 21:56

Barmar · Accepted Answer · 2015-09-23 22:14:00Z

3

To call a function, you have to put () after it. Since colors() returns the function, put () after the call to colors:

$(document).ready(function(){
    colors(function(){alert('Orange');})();
});

More generally, the way you deal with callbacks is something like:

callback = getCallback(args);
callback();

edited Sep 23, 2015 at 22:14

answered Sep 23, 2015 at 21:56

Barmar

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3 Comments

Pointy Over a year ago

This may very well be what the OP is (mysteriously) trying to do :)

Barmar Over a year ago

I suspect it's a simplification -- he may be calling a function that returns a function from a table of some kind.

Rodrigo Calix Over a year ago

i'm creating a plugin, for animations, so when de animation ends, if the user want, can make a callback

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