Array exception ArrayIndexOutOfBoundsException

Question

I want to ask something because I don't understand something. I want to found min element in array, when I use this code it is fine:

public static int najmanji(int[] niz) {
    int min = niz[0];
    for (int el = 0; el<niz.length; el++) {
        if (niz[el] < min) {
            niz[el] = min;
            return min;
        }
    }

    return min;

}

But when I use foreach loop I have exception ArrayIndexOutOfBoundsException.

public static int najmanji(int[] niz) {
    int min = niz[0];
    for (int el : niz){
        if (niz[el] < min) {
            niz[el] = min;
            return min;
        }
    }

    return min;
 }

Why I have this error? Because foreach is same like for loop?

@Blue Master also your min function is not returning min. Example:int[] datas1 = {5,6,7,8,4,3,2,1}; najmanji(datas1) would return 5, which is clearly not the min. Use this: public static int najmanji2(int[] niz){ int min=niz[0]; for(int el=0;el<niz.length;el++){ if(niz[el]<min){ min = niz[el]; } } return min; } — alainlompo
– alainlompo, Commented Sep 24, 2015 at 0:41

Michael · Accepted Answer · 2015-09-24 00:21:58Z

2

el does not represent an index; it's the actual value.

for(int i = 0; i < myArray.length; i++){
    int curVal = myArray[i];
    //your code...
}

Is the same as

for (int curVal : myArray){
    //your code...
}

answered Sep 24, 2015 at 0:21

Michael

2,8111 gold badge19 silver badges27 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Array exception ArrayIndexOutOfBoundsException

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related