In scala I would like to dynamically allocate an array of sequential index values.
In R it is simply maxindex = 10 then array = 1:maxindex which returns 1,2,3,4,5,6,7,8,9,10
Is it possible to do this in scala?
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2 Answers
You should try Range method:
Range(val start : Int, val end : Int, val step : Int)
You could use it like this:
var yourArray = range(1, 10, 1)
That will return an array like you want: 1,2,3,4,5,6,7,8,9,10
Or even more simple:
var yourArraySimpler = 1 until 11
Take a look at the documentation. From the link:
The Range class represents integer values in range [start;end) with non-zero step value step. Sort of acts like a sequence also (supports length and contains).
It is as simple as:
val arr = 1 to 10
which uses an implicit conversion to generate a Range as described in @cacho's answer. Range is a subclass of Seq, but you can call .toArray on it if you specifically need an array.
