I need a regex for validating a string / decimal in JavaScript.
Which can be max 9 elements long with 2 decimals
Simply
123 - valid
123456789 - valid
1234567896 - invalid ( max 10 chars )
123. - invalid
123.2 - valid
123.32 valid
123.324 invalid ( 3 decimal points )
So I wrote a regexp like this
/^([0-9]{1,9})+[.]+([0-9]{0,2})$/
Can any one plz fine tune this regex
You can use regex ^(?=.{0,10}$)\d{0,9}(\.\d{1,2})?$
$('input').on('input', function() {
$(this).css('color', this.value.match(/^(?=.{0,10}$)\d{0,9}(\.\d{1,2})?$/) ? 'green' : 'red');
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input type=text/>
Give the following a try:
^\d{1,9}(\.\d{1,2})?$
Something like this?
/^[0-9]{1,9}(\.[0-9]{0,2})?$/
Which can be max 9 elements long with 2 decimalsYou may use a negative lookahead at the beginning to apply a length restriction to the whole match:
^(?!\S{10})\d+(?:\.\d{1,2})?$
See regex demo
^ - start of string(?!\S{10}) - no more than 9 non-whitespace characters from the beginning to end condition\d+ - 1 or more digits(?:\.\d{1,2})? - 1 or zero groups of . + 1 or w2 digits$ - end of stringHowever, you might as well just match the float/integer numbers with ^\d+(?:\.\d{1,2})?$ and then check the length of the matched text to decide whether it is valid or not.
Note that in case you have to omit leading zeros, you need to get rid of them first:
s = s.replace(/^0+/, '');
And then use the regex above.
12345678.12should be invalid?