I am writing a bash function.
How do I make the control exit the function as soon as any command in it error out?
I have tried this:
function myFunc() {
set +e
cmd1
cmd2
set -e
}
It works but it closes my terminal as well.
Appreciate any ideas.
Thanks.
"exit" means exit the shell. If you want to return from the function, you need to "return", which you can only do manually:
myFunc() {
cmd1 || return $?
cmd2 || return $?
}
If you really want to use set -e, use a subshell as well:
myFunc () {
(
set -e
cmd1
cmd2
) || return $?
}
Also consider using && to create a chain of commands each contingent on the success of the previous ones.
Separate them by &&:
cmd1 && cmd2 && cmd3
For truth tests without set -e one can test the value of #? to reveal the status of the last command:
#!/bin/bash
myfunc()
{
true
[ "$?" = "0" ] || return
printf "passed truth test 1\n"
true
[ "$?" = "0" ] || return
printf "passed truth test 2\n"
false
[ "$?" = "0" ] || return
printf "passed false test\n"
}
myfunc
printf "passed continuation test\n"
cmd1 || return; cmd2 || return?